Which of the following ions is the strongest | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of $Ce$ $(Z=58)$ is $[Xe] 4f^1 5d^1 6s^2$. $Ce^{4+}$ is stable due to noble gas configuration,making $Ce^{3+}$ a redu

Vedclass · Accepted Answer

$Tb^{4+}$

Vedclass · Answer

(C) The electronic configuration of $Ce$ $(Z=58)$ is $[Xe] 4f^1 5d^1 6s^2$. $Ce^{4+}$ is stable due to noble gas configuration,making $Ce^{3+}$ a reducing agent.$Tb$ $(Z=65)$ has configuration $[Xe] 4f^9 6s^2$. $Tb^{4+}$ has a $4f^7$ configuration,which is half-filled and stable,but $Tb^{4+}$ itself is a strong oxidizing agent because it readily gains an electron to achieve the stable $4f^7$ configuration from a $4f^8$ state (if it were $Tb^{3+}$) or simply acts as a strong oxidant to return to the stable $Tb^{3+}$ state.Among the given options,$Tb^{4+}$ is the strongest oxidizing agent because it has a high tendency to be reduced to $Tb^{3+}$.

Which of the following ions is the strongest oxidizing agent? [ Atomic Number of $Ce = 58, Eu = 63, Tb = 65, Lu = 71$ ]

Similar Questions

What is the number of unpaired electrons present in $f$-orbital at $+3$ oxidation state of $Lu (Z=71)$?

Name a member of the lanthanoid series which is well known to exhibit $+4$ oxidation state.

Most common oxidation states of $Ce$ $(cerium)$ are

In $f$-block elements,which orbitals are progressively filled by electrons?

Vedclass Test Series

Exam Paper Generator

Online Exam Module